Take A Break…

You owe yourself:

(don’t forget your coffee)

The Good

**

The Bad

**

The Ugly

Adam is given 52 cards from his friend, and he knows in that pile are 13 cards that are facing up and the rest are facing down in a random order. Adam is blindfolded and cannot see the cards. He needs to create two piles with the same number of cards facing up.

How can he do it? Not a trick question.

This one is a nasty…don’t be too harsh on yourself.

**

Answers in the Comments as always.

End

Source: facebook.com/Elec.Eng.World, braingle.com (Xpert007 and Crazycriely) and Brightside.com

Advertisements

8 Responses to Take A Break…

  1. tskraghu says:

    Answers:

    The Good: He was on a walk!

    The Bad: For stability, it’s reasonable to assume a symmetrical backside. So it is at least 15 + 15 +1 = 31.

    The Ugly: Adam needs to take the first 13 cards from the top and simply flip them over. That’s it. Done.

    If you don’t believe us, let’s check it out.

    Here is an example: You took the first 13 cards from the top and let’s say, there are nine facing-up cards in that first pile. This means that the remaining pile would have only 4 facing-up cards as we know from the beginning, that 13 out of the 52 cards were facing up. If you flip the first pile over, four cards will be facing up and nine will be facing down.

    Thank you.

    Like

  2. Nithya says:

    Me and kids got #1. Getting 30 on #2.

    Liked by 1 person

  3. Vidya says:

    Brain tease ! All good n simple Don’t ask me how much I scored !

    Liked by 1 person

  4. psriblog says:

    I think answer to #2 is 30, not 31. The bottom row has 16, the next row has 9, the next row has 4 and the top has 1. It is 30, according to me.

    The puzzle 3 is the best one, actually, and puzzle 1 is the easiest!

    Liked by 1 person

    • tskraghu says:

      It is assumed by the riddle/puzzle-master the balls are repeated at the back. except the top one to get 31. If we assume the two edges on the right and left are shared between the front and the back, one gets 4+3 for the edges plus twice the remaining nine = 25!

      Thanks.

      Like

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

%d bloggers like this: